 Anders Str&#248;m M&#248;ller - 3 years ago 189
Java Question

# Processing, making an analog clock, the numbers

so, as an assaignment i want to make an analog clock, and i am pretty far. I only need the numbers around the clock, but i cant figure out how to make these. I have made some dots right now, but i want to replace theese with the numbers 1-12.. does any1 know an easy and fast way of doing this? my code is as following:

``````    int cx, cy;
float clockDiameter;

void setup() {
size(1366,768);
stroke(255);

float radius = min(width/1.2, height/1.2) / 2;

cx = width / 2;
cy = height / 2;
}

void draw() {
background(random(0,255),random(0,255),random(0,255));

// Draw the clock background
fill(0);
noStroke();
ellipse(cx, cy, clockDiameter, clockDiameter);

// Angles for sin() and cos() start at 3 o'clock;
// subtract HALF_PI to make them start at the top
float s = map(second(), 0, 60, 0, TWO_PI) - HALF_PI;
float m = map(minute() + norm(second(), 0, 60), 0, 60, 0, TWO_PI) - HALF_PI;
float h = map(hour() + norm(minute(), 0, 60), 0, 24, 0, TWO_PI * 2) - HALF_PI;

// Draw the hands of the clock
stroke(255);
strokeWeight(1);
line(cx, cy, cx + cos(s) * secondsRadius, cy + sin(s) * secondsRadius);
strokeWeight(2);
line(cx, cy, cx + cos(m) * minutesRadius, cy + sin(m) * minutesRadius);
strokeWeight(4);
line(cx, cy, cx + cos(h) * hoursRadius, cy + sin(h) * hoursRadius);

// Draw the dots arround the clock
strokeWeight(2);
beginShape(POINTS);
for (int a = 0; a < 360; a+=30) {
float x = cx + cos(angle) * secondsRadius;
float y = cy + sin(angle) * secondsRadius;
vertex(x, y);
}
endShape();
textSize(40);
text("Dank Clock", 570,40);
}
`````` Kevin Workman

You already have a loop that goes around the clock and places dots at the clock positions. Now all you need is some logic that draws the hour at those positions.

Processing has a `text()` function that allows you to draw text (or numbers) to the screen. You can just call that instead of `vertex()` to draw the hours.

To get the hours to draw, just use an `int` variable that you increment each time through the loop. Something like this:

``````  int hour = 3;
for (int a = 0; a < 360; a+=30) {
float x = cx + cos(angle) * secondsRadius;
float y = cy + sin(angle) * secondsRadius;
vertex(x, y);
fill(255);

text(hour, x, y);
hour++;
if(hour > 12){
hour = 1;
}
}
``````

Notice that I'm starting at `3` because your angle starts at `0`, which points all the way to the right. When the loop goes over the 12, I just start `hour` back over at `1`.

You could probably also figure out a simple formula that maps from `a` to an hour, that way you don't have to do the incrementing yourself.

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