Ragith Thomas Ragith Thomas - 27 days ago 11
PHP Question

how to pass a values from the database to the json in php

Thanks in advance, I have a three salary data in the table column. I am using while loop to display three salary values in the view page. But I have to pass these three values to three variables in json like {salary1:$sal1,salary2:$sal2,salary3:$sal3}. How to seperate looped three salary values into three variables

My code as below:

<table border="1">
<caption><h2>View Registration</h2></caption>
<tr>
<th>Name</th>
<th>Designation</th>
<th>Email</th>
<th>Salary</th>
<tr>
<?php

include('common.php');
$sql = mysql_query("select * from register");
while($row = mysql_fetch_array($sql))
{

?>
<tr>
<td><?php echo $row['name']?></td>
<td><?php echo $row['designation']?></td>
<td><?php echo $row['email']?></td>
<td><?php

$salary = $row['salary'];
echo $salary;


?></td>
<tr>
<?php
}


?>
</table>

Answer

create an array of all salary and echo with json_encode, array will be convert in to json as you wants,

$sql = mysql_query("select * from register");

$salary =array();
while ($row = mysql_fetch_array($sql)) {
    $salary[$row['name']] = $row['salary'];
}
echo json_encode($salary);