user3624406 - 1 year ago 55

Python Question

This is what is available right now

`l = [list[0]]`

list.pop(0)

x = len(list)

for i in range(x+1):

n = len(l)

j = 0

if list[j] > l[n-1]:

l.append(list[j])

list.pop(j)

j = j+1

elif i == len(list):

l.append(list[j])

list.pop(j)

print(list)

print(l)

`

Some pointers would be really helpful!

Answer Source

Make a `copy`

of the list. Iterate through the copy in *successions* and check for monotonically increasing entries to be added to `result`

in the current iteration of the `while`

loop. Delete the entries as they are added to the `result`

.

Repeat the *check-append-delete* cycle in the next iteration of the while loop; until the copy of the list is empty:

```
lst = [1, 2, 2, 2, 11, 5, 9, 8, 19]
lst_cp = lst.copy()
result = []
while lst_cp: # keep iterating until list is empty
result.append(lst_cp.pop(0))
for v in lst_cp[:]:
if v > result[-1]:
result.append(v)
lst_cp.remove(v)
print(result)
# [1, 2, 11, 19, 2, 5, 9, 2, 8]
```