Skemelio Skemelio - 1 year ago 67
C# Question

How do I apply column and row styles on a TableLayoutPanel programmatically?

In the beginning there is a TableLayoutPanel with only one row and no columns. By the press of a button I want this panel to be transformed with 5 rows and 3 columns.

private void button_Click(object sender, EventArgs e)
this.tableLayoutPanel1.ColumnCount = 3;
this.tableLayoutPanel1.RowCount = 5;

The problem is that you get this as a result!

enter image description here

The boxes that are created with the rows and columns do not contain the same area in the panel, as you can see.

In the case of 3 columns and 5 rows, the columns must share the 100% of the tablelayoutpanel, so 30% per each. In the case of 5 rows, each row must take 20%.

So I append to the button_Click method the next two lines of code.

this.tableLayoutPanel1.ColumnStyles.Add(new ColumnStyle(SizeType.Percent, 30F));
this.tableLayoutPanel1.RowStyles.Add(new RowStyle(SizeType.Percent, 20F));

But I get the same result!
What I am missing?

Answer Source

Probably you are adding styles to an already defined TableLayoutPanel without resetting the current styles.

tableLayoutPanel1.CellBorderStyle = TableLayoutPanelCellBorderStyle.Single;
tableLayoutPanel1.Dock = DockStyle.Fill;


tableLayoutPanel1.RowCount = 5;
for(int x = 0; x < tableLayoutPanel1.RowCount; x++)
    tableLayoutPanel1.RowStyles.Add(new RowStyle() { Height = 20, SizeType = SizeType.Percent });
tableLayoutPanel1.ColumnCount = 3;
for(int x = 0; x < tableLayoutPanel1.ColumnCount; x++)
    tableLayoutPanel1.ColumnStyles.Add(new ColumnStyle() { Width = 33, SizeType = SizeType.Percent });