user3514538 user3514538 - 1 year ago 54
C++ Question

Overload resolution between const lvalue reference and rvalue reference

#include <iostream>
#include <string>

void fnc (const std::string&)

void fnc (std::string&&)

int main()
fnc ("abc");

All the compilers choose
version of
, and it is logical, because the temporary
is created for a reference binding, but I can't find, where is it described in C++ 14 Standard.
I found one paragraph in there (3.2):

— Standard conversion sequence S1 is a better conversion sequence than
standard conversion sequence S2 if


— S1 and S2 are reference bindings (8.5.3) and neither refers to an
implicit object parameter of a non-static member function declared
without a ref-qualifier, and S1 binds an rvalue reference to an rvalue
and S2 binds an lvalue reference

But it isn't that case, because S1 binds an rvalue reference to an lvalue ("abc", lvalue of const char[4]).
Where can I find description, by which the second overload is selected?

P.S. I pointed to C++14 Standard instead of C++11, because I know, that there was some defect reports in C++11, linked with rvalue reference binding.

Answer Source

First the compiler performs an implicit lvalue-to-rvalue conversion for "abc", so the type of "abc" becomes const char*. Second (and you probably missed that), const char* is converted to a rvalue std::string via the const char* non-explicit constructor of std::string (# 5 in the link). The constructed std::string rvalue is a perfect match for the second overload, so the second overload is chosen.

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