LutraLutra LutraLutra - 2 months ago 34
Java Question

Apache CXF - None of the policy alternatives can be satisfied

I'm trying to create client of 3rd party WS. My app is running on JBoss AS 6 (with its Apache CXF 2.3.1 stack). I generated client code by wsconsume (wsdl2java). When I tried to connect to WS a got exception:

No assertion builder for type http://schemas.microsoft.com/ws/06/2004/policy/http}BasicAuthentication registered.
Exception in thread "main" org.apache.cxf.ws.policy.PolicyException: None of the policy alternatives can be satisfied.


Auth part of WSDL looks like:

<wsp:Policy wsu:Id="abc_ssl_policy">
<wsp:ExactlyOne>
<wsp:All>
<http:BasicAuthentication
xmlns:http="http://schemas.microsoft.com/ws/06/2004/policy/http" />
<sp:TransportBinding
xmlns:sp="http://schemas.xmlsoap.org/ws/2005/07/securitypolicy">
<wsp:Policy>
<sp:TransportToken>
<wsp:Policy>
<sp:HttpsToken RequireClientCertificate="false" />
</wsp:Policy>
</sp:TransportToken>
<sp:AlgorithmSuite>
<wsp:Policy>
<sp:Basic256 />
</wsp:Policy>
</sp:AlgorithmSuite>
<sp:Layout>
<wsp:Policy>
<sp:Strict />
</wsp:Policy>
</sp:Layout>
</wsp:Policy>
</sp:TransportBinding>
</wsp:All>
</wsp:ExactlyOne>
</wsp:Policy>


Client code:

@WebServiceClient(name = "Abc",
wsdlLocation = "https://hiddendomain.com/abc/abc.svc?wsdl",
targetNamespace = "http://tempuri.org/")
public class Abc extends Service {

public final static URL WSDL_LOCATION;

public final static QName SERVICE = new QName("http://tempuri.org/", "Abc");
public final static QName AbcSsl = new QName("http://tempuri.org/", "abc_ssl");
static {

Authenticator.setDefault(new Authenticator() {
@Override
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication("user", "pas".toCharArray());
}

});

URL url = null;
try {
url = new URL("https://hiddendomain.com/abc/abc.svc?wsdl");

} catch (MalformedURLException e) {
java.util.logging.Logger.getLogger(DistrInfo.class.getName())
.log(java.util.logging.Level.INFO,
"Can not initialize the default wsdl from {0}", "...");
}
WSDL_LOCATION = url;
}


Exception is thrown whe I try get Conduit:

Client client = ClientProxy.getClient(port);
HTTPConduit con = (HTTPConduit) client.getConduit(); <- exception


I suspect that is because of non-standard MS policy and I need proper Intercerptor to handle this policy, but can somebody show me a way how to do it?

I dont even no, where I should put my HTTPS credentials to auth (I can't get conduit)

Answer

The problem gone when I used this code:

import org.apache.cxf.endpoint.Client;
import org.apache.cxf.frontend.ClientProxy;
import org.apache.cxf.jaxws.JaxWsProxyFactoryBean;
import org.apache.cxf.transport.http.HTTPConduit;

...

JaxWsProxyFactoryBean factory = new JaxWsProxyFactoryBean();

//factory.getInInterceptors().add(new LoggingInInterceptor());
//factory.getOutInterceptors().add(new LoggingOutInterceptor());

factory.setServiceClass(IAbc.class);
factory.setAddress("https://hiddendomain.com/abc/abc.svc/soap"); <- must be /soap there, otherwise 404

IAbc info = (IAbc) factory.create();

Client client = ClientProxy.getClient(info);
HTTPConduit http = (HTTPConduit) client.getConduit();

http.getAuthorization().setUserName("user");
http.getAuthorization().setPassword("pass");

String abc = info.abc();
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