Shreya Basu - 1 month ago 4x

Python Question

Example: If the first number in the sample is 1, then the next number can only be 2, 4 or 5, and if the second number is 2, then the next number can only be 1, 3, 4, 5 or 6. This continues for all the numbers in the list.

I tried using this:

`import random`

num_list = [1,2,3,4,5,6,7,8,9]

new_sample = random.sample(num_list, 5)

print (new_sample)

However, I can't seem to manipulate this code so that it follows the conditions I need. Any help would really be appreciated.

EDIT: The pattern in the conditions is a bit hard to explain.

The numbers 1 to 9 come from a 3 x 3 grid of dots numbered in order from left to right and top to bottom. I'm trying to simulate random patterns such that you can only join adjacent dots.

If the preceding number (PN) = 1, then the next number (NN) = 2, 4 or 5, If PN = 2, then NN = 1, 3, 4, 5 or 6, If PN = 3 then NN = 2, 5, 6, If PN = 4 then NN = 1, 2, 5, 7, or 8, If PN = 5 then NN = 1, 2, 3, 4, 6, 7, 8, or 9 and so on.

Answer

I think this will work (in Python 3):

```
import random
x_arr=[]
y_arr=[]
def addTolist(m,n):
x_arr.append(m)
y_arr.append(n)
grid = [[1,2,3],[4,5,6],[7,8,9]]
new_sample = random.sample(range(1,10), 5) # to generate random list of 5 numbers
current = random.choice(new_sample) # take random number from list of 5 numbers
for i in range(3): # to position of number in the grid
for j in range(3):
if current == grid[i][j]:
x = i
y = j
break
num = [current] # to store the unique random numbers
for i in range(4): # loop till we find the 5 th number
print('current:',current)
# every time empty the list
neighbours = []
x_arr=[]
y_arr=[]
# to choose the neighbours of current number (maximum 8 neighbours)
if y-1 >= 0:
neighbours.append(grid[x][y-1])
addTolist(x,y-1)
if x+1 < 3:
neighbours.append(grid[x+1][y-1])
addTolist(x+1,y-1)
if x-1 >= 0:
neighbours.append(grid[x-1][y-1])
addTolist(x-1,y-1)
if x-1 >= 0:
neighbours.append(grid[x-1][y])
addTolist(x-1,y)
if y+1 < 3:
neighbours.append(grid[x-1][y+1])
addTolist(x-1,y+1)
if y+1 < 3:
neighbours.append(grid[x][y+1])
addTolist(x,y+1)
if x+1 < 3:
neighbours.append(grid[x+1][y+1])
addTolist(x+1,y+1)
if x+1 < 3:
neighbours.append(grid[x+1][y])
addTolist(x+1,y)
current = random.choice(neighbours)
while current in num: # till unique random number is not generted
current = random.choice(neighbours)
num.append(current)
position = neighbours.index(current)
x = x_arr[position]
y = y_arr[position]
print("x position:",x_arr)
print("y position:",y_arr)
print("neighbours:",neighbours)
print("Final Number : ",current)
```

Output:

```
current: 7
x position: [1, 1, 2]
y position: [0, 1, 1]
neighbours: [4, 5, 8]
current: 4
x position: [0, 0, 1, 2, 2]
y position: [0, 1, 1, 1, 0]
neighbours: [1, 2, 5, 8, 7]
current: 5
x position: [1, 2, 0, 0, 0, 1, 2, 2]
y position: [0, 0, 0, 1, 2, 2, 2, 1]
neighbours: [4, 7, 1, 2, 3, 6, 9, 8]
current: 8
x position: [2, 1, 1, 1, 2]
y position: [0, 0, 1, 2, 2]
neighbours: [7, 4, 5, 6, 9]
Final Number : 9
```

Assumption :grid is 3*3 And You have to find the 5th number always.

It is bit lengthy but I have to check all neighbours in `3*3`

grid.
So I take `grid`

variable which is list of list numbers in grid similar to *2D array*. I think all the remaining code is self explanatory.

Hope this will help you.

Source (Stackoverflow)

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