kockiren kockiren - 1 year ago 57
Perl Question

How to get line break in E-Mail from shellscript?

There is a shell script (bash) that check a csv file for lines that don't match a pattern and send a mail with the wrong lines. Thats works fine but while combine the wrong lines linux give a \r as line break, in the E-Mail there is no linebreak. So I try to send \r\n as line break but this has no effect, perl or bash delete this \n newline.

Here is a minimal working script as example:

SUBJECT="Error while parse CSV"
wrongLines=$(perl -ne 'print "Row $.: $_\r\n" if not /^00[1-9]\d{4,}$/' $file)
MESSAGE="Error while parse following Lines, pattern dont match: \r\n $wrongLines"
echo $MESSAGE |od -c

The output of od is:

0000000 E r r o r w h i l e p a r s
0000020 e f o l l o w i n g L i n e
0000040 s , p a t t e r n d o n t
0000060 m a t c h : \ r \ n R o w
0000100 2 : 4 9 2 7 8 3 8 7 4 3 \r R
0000120 o w 3 : 4 8 2 3 2 8 9 7 3 8
0000140 \r \n

But what is the reason that in the od output the \n between the rows is deleted? I also try \x0D\x0A instead of \r\n but this also don't help. Any suggestions?

Answer Source

Your problem is that you're not using quotes!


$ a="A multi-line
$ echo $a
A multi-line input variable
$ echo "$a"
A multi-line

Without quotes, you'll be victim of word splitting and filename expansion (not illustrated in the example above).

Also, adding \r or \n (that is, verbatim backslash followed by r or n) is not going to help at all.

Conclusion: Quote every variable expansion! always! (unless you really mean a glob pattern — in which case you will also add a comment in the code to explain why you purposely didn't quote the expansion).

Side note: don't use upper case variable names!

It is recommended you use lower-case names for your own parameters so as not to confuse them with the all-uppercase variable names used by Bash internal variables and environment variables.

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