I have a exercise ,Input data will contain the total count of pairs to process in the first line.
The following lines will contain pairs themselves - one pair at each line.
Answer should contain the results separated by spaces.
n = int(raw_input())
sum = 0
for i in range(n):
y = raw_input().split(" ")
for i in y:
sum = sum + int(i)
with your current code what you get is the total sum of all the given numbers, to get the sum per line you need to initialize your counter in the outer loop, and then print it, and as you want to print all it in the same line there are several ways to do it, like save it in a list or telling print that don't print a new, line which is done by adding a
, at the end like
print x, with that in mind then the changes needed are
n = int(raw_input()) for i in range(n): pairs = raw_input().split() #by default split use spaces pair_sum = 0 for p in pairs: pair_sum += int(p) # a += b is the same as a = a + b print pair_sum, print "" # to print a new line so any future print is not done in the same line as the previous one
that was the version with print per line, next is the version using list
n = int(raw_input()) resul_per_line =  for i in range(n): pairs = raw_input().split() #by default split use spaces pair_sum = 0 for p in pairs: pair_sum += int(p) # a += b is the same as a = a + b resul_per_line.append( str(pair_sum) ) #conver each number to a string to use with join bellow print " ".join(resul_per_line)
with either of the above let said for example that the input data is
3 1 2 40 50 600 700
then the result would be
3 90 1300
pair_sum = 0 for p in pairs: pair_sum += int(p)
pair_sum = sum( map(int,pairs) )