giorgosan - 1 year ago 75

Python Question

When I give for example: -2 or -8, I get 110, 11000. But I want to get 10, 1000, because it must use the minimum binary numbers. So I have to use another way to the negative ones. I tried to swap 1 and 0 until I reach LSB 1, but I can't find a way.

(To help you: dekadikos = demical, diadikos = binary, boith = assistant)

`dekadikos = input()`

while dekadikos != "end" :

dekadikos = int(dekadikos)

if dekadikos > 0 :

diadikos = bin(dekadikos)

diadikos = (diadikos[2:])

n = int(len(diadikos)) + 1

print(diadikos.zfill(n))

elif dekadikos == 0 :

diadikos = bin(dekadikos)

diadikos = (diadikos[2:])

print(diadikos)

else :

dekadikos = abs(dekadikos)

diadikos = bin(dekadikos)

diadikos = (diadikos[2:])

n = int(len(diadikos)) + 1

diadikos = diadikos.zfill(n)

boithdekadikos = 2**n - dekadikos

diadikos = bin(boithdekadikos)

diadikos = diadikos[2:]

print (diadikos)

dekadikos = input()

Answer Source

You could solve it by making two changes to your code of the last `else`

block (commented):

```
else :
dekadikos = abs(dekadikos)
diadikos = bin(dekadikos-1) # subtract 1
diadikos = (diadikos[2:])
n = int(len(diadikos)) + (dekadikos>1) # add 1 except for 1
diadikos = diadikos.zfill(n)
boithdekadikos = 2**n - dekadikos
diadikos = bin(boithdekadikos)
diadikos = diadikos[2:]
print (diadikos)
```

It seems like a lengthy method though, to get to your desired result. For one, you could use `format(dekadikos, 'b')`

to get the binary representation of a number without the `0b`

prefix.

You could do this instead, which covers positive, zero and negative:

```
dekadikos = int(dekadikos)
diadikos = '0' + format(abs(dekadikos)-(dekadikos<0), 'b')
if dekadikos == 0:
diadikos = '0'
elif dekadikos < 0:
diadikos = format(2**(len(diadikos)-(dekadikos==-1)) + dekadikos, 'b')
print (diadikos)
```