burakkaanerce - 1 year ago 126

Java Question

I need a task about finding Fibonacci Sequence for my independent project in Java. Here are methods for find.

`private static long getFibonacci(int n) {`

switch (n) {

case 0:

return 0;

case 1:

return 1;

default:

return (getFibonacci(n-1)+getFibonacci(n-2));

}

}

private static long getFibonacciSum(int n) {

long result = 0;

while(n >= 0) {

result += getFibonacci(n);

n--;

}

return result;

}

private static boolean isInFibonacci(long n) {

long a = 0, b = 1, c = 0;

while (c < n) {

c = a + b;

a = b;

b = c;

}

return c == n;

}

Here is main method:

`long key = getFibonacciSum(n);`

System.out.println("Sum of all Fibonacci Numbers until Fibonacci[n]: "+key);

System.out.println(getFibonacci(n)+" is Fibonacci[n]");

System.out.println("Is n2 in Fibonacci Sequence ?: "+isInFibonacci(n2));

Codes are completely done and working. But if the n or n2 will be more than normal (50th numbers in Fib. Seq.) ? Codes will be runout. Are there any suggestions ?

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Answer Source

Yes, one improvement you can do is to `getFibonacciSum()`

: instead of calling again and again to `isInFibonacci`

which re-calculates everything from scratch, you can do the exact same thing that `isInFibonacci`

is doing and get the sum in one pass, something like:

```
private static boolean getFibonacciSum(long n) {
long a = 0, b = 1, c = 0, sum = 0;
while (c < n) {
c = a + b;
a = b;
sum += b;
b = c;
}
sum += c;
return sum;
}
```

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