As I know, heap tables are tables without clustered index and has no physical order.
I have a heap table "scan" with 120k rows and I am using this select:
SELECT id FROM scan
SQL Server indices are b-trees. A non-clustered index just contains the indexed columns, with the leaf nodes of the b-tree being pointers to the approprate data page. A clustered index is different: its leaf nodes are the data page itself and the clustered index's b-tree becomes the backing store for the table itself; the heap ceases to exist for the table.
Your non-clustered index contains a single, presumably integer column. It's a small, compact index to start with. Your query
select id from scan has a covering index: the query can be satisfied just by examining the index, which is what is happening. If, however, your query included columns not in the index, assuming the optimizer elected to use the non-clustered index, an additional lookup would be required to fetch the data pages required, either from the clustering index or from the heap.
To understand what's going on, you need to examine the execution plan selected by the optimizer: