Can't pass /bin/*

Question

I am trying to pass a to fill an array with a list of directories using a simple shell script. However when I pass

/bin/*

into the program as the first parameter

$1

turn to

/bin/bash

(the first directory in /bin). My code is below for reference. Can I not pass

*

in a parameter?

#!/bin/bash



declare -a d

placeholder=0



for filename in ${1}; do

     d[${placeholder}]=${filename:5}

     ((placeholder++))

 done



echo "$1"

The result of the echo is

/bin/bash

Thanks!

Recommended for you: Get network issues from WhatsUp Gold. Not end users.

Answer 1

* is being expanded by the shell before it calls your script. Try calling as yourscript '/bin/*' (note the quotes).

Can't pass /bin/*

Sign up