Demetri P - 1 year ago 95

Python Question

From the R Documentation...

bw.nrd0 implements a rule-of-thumb for choosing the bandwidth of a

Gaussian kernel density estimator. It defaults to 0.9 times the

minimum of the standard deviation and the interquartile range divided

by 1.34 times the sample size to the negative one-fifth power (=

Silverman's ‘rule of thumb’, Silverman (1986, page 48, eqn (3.31))

unless the quartiles coincide when a positive result will be

guaranteed.

On an array from 1 to 400 (equivalent to

`np.arange(1,401)`

`def nrd0_python(x):`

X = min(np.std(x), np.percentile(x,25))

top = 0.9*X

bottom = 1.34*len(x)**(-0.2)

return top/bottom

I get upwards of 200 (to be exact, 224.28217762858455)

Are there any known python functions for silverman's rule of thumb?

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Answer Source

The precedence of operators in an English sentence is ambiguous.

Here's an implementation that returns the value you expect:

```
In [201]: x = np.arange(1, 401)
In [202]: 0.9*min(np.std(x, ddof=1), (np.percentile(x, 75) - np.percentile(x, 25))/1.349)*len(x)**(-0.2)
Out[202]: 31.393668650034652
```

I don't have the Silverman reference. I found that in http://darp.lse.ac.uk/papersdb/Cowell-Flachaire_Handbook.pdf (p. 21).

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