Expression must be an array, but ... to double

Question

I am trying to practice writing some code and I can't solve my problem here.
I keep getting for "double sideA,sideB,sideC" that the expression must be an array, but it resolved to double.

public static double Calculate (double array1, double array2, double array3) {



            double sideA = Math.sqrt(((array2[0]-array3[0])^2)+((array2[1]-array3[1])^2)+((array2[2]-array3[2])^2));

            double a= Math.abs(sideA);

            double sideB = Math.sqrt(((array1[0]-array3[0])^2)+((array1[1]-array3[1])^2)+((array1[2]-array3[2])^2));

            double b= Math.abs(sideB);

            double sideC = Math.sqrt(((array2[0]-array1[0])^2)+((array2[1]-array1[1])^2)+((array2[2]-array1[2])^2));

            double c= Math.abs(sideC);

            double s = ((0.5) * (a + b + c));

            return Math.sqrt(s * (s - a) * (s - b) * (s - c));

    }

so can someone please help?

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Answer 1

array1, despite the name, is not actually an array as you've written the code right now. As you've written it, array1 is just a single number.

Instead, it should be

public static double calculate(double[] array1, double[] array2, double[] array3) {

(Also, ^ does not do what you think it does; you would need Math.pow. On the other hand, you can just write Math.hypot(array2[0] - array1[0], array2[1] - array1[1]).)

Expression must be an array, but ... to double

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