Python Question
Reading Specific Python list from a text file
I am currently Trying to read all data Occurring after a colon ':' in a file for example.
In a text file containing only:
SAM Account Type : 805306368
with open("Sample.txt") as myfile:
for line in myfile:
flag=0
if ("SAM Account Type" in line):
for ch in line:
if (flag and ch!=' ' and ch!='\n'):
B+=ch
elif (ch == ':'):
flag+=1
S1 = myfile.read(10)
# print (ch)
elif (ch=='\n'):
flag =0
else:
pass
print (B)
This works like a charm only showing me "805306368"
But when I try to check for more variable other than "SAM Account Type" by using a list it fails to give the correct output.
For example the file below:
SAM Account Name : Ramachandran. S
SAM Account Type : 805306368
Description :
User Account Control : 544
When Created:09/21/2015 06:33:53
Lastlogontimestamp : 130966421275783509
When Changed : 01/07/2016 12:08:47
Account Expires : 922337203685477580
Last logoff : 00:00:00.0000000
Last logon : 130971364125825724
and this following code :
A = []
A.extend({"SAM Account Type",
"User Account Control",
"Last logon",
"Lastlogontimestamp",
"Last logoff",
"Account Expires"})
B = ""
with open("Sample.txt") as myfile:
for line in myfile:
for i in range(len(A)):
flag=0
if (str(A[i]) in line):
#if ("SAM Account Type" in line):
for ch in line:
if (flag and ch!=' ' and ch!='\n'):
B+=ch
elif (ch == ':'):
flag+=1
S1 = myfile.read(10)
elif (ch=='\n'):
flag =0
else:
pass
print (B)
B=""
Which Reads all the Characters after a ':' which Belong to an Entity in the list 'A' Stores them in 'B', and prints B for each line.
Gives The following:
'805306368'
'544'
'130966421275783509'
'922337203685477580'
'130971364125825724'
When it should also give for 'Last logoff' which is '00:00:00.0000000'
But it doesn't work. Any help would be highly appreciated.
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Answer Source
As you are scanning for specific strings (ie those in A) I would create a list of each line in your file.
Split each line by ' : ' which seems to be the standard break between your key and your values in your txt file.
You now have a list that you can scan B and compare the first element of this list to the contents of A. We can print the second element (what appears after ' : ' for each match:
B=[]
with open("Sample.txt") as f:
for line in f:
B.append(line.split(' : ')
for i in B:
if i[0] in A:
print i[1].strip() #this removes the \n
Another 'fun' way to do this would be to create a dictionary
c={}
with open("Sample.txt") as f:
for line in f:
t=line.split(' : ')
c.update({t[0]:t[1].split()})
for i in set(c.keys()) & set(A): #gives set of matches between keys and A
print c[1]
If you're into the whole brevity thing:
for i in open("Sample.txt").readlines():
if i[:i.index(' : ')] in A:
print i[i.index(' : ')+3:].split()[0]
Lastly:
print ''.join([i[i.index(' : ')+3:] for i in open("Sample.txt").readlines() if i[:i.index(' : ')] in A])
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