Jenny M Jenny M - 4 months ago 20
Node.js Question

Excute command in gulp for sub folder

My project is structured as follows:

myapp
-server.js
-test
--testcontent
---package.json
-package.json


I have two
package.json
files and I want to run
npm install
on the
package.json
inside the
testcontent
folder.

If in the command line I go to
myapp/test/testcontent
and run
npm install
it works and it creates a new folder
node_modules
with the dependencies from the correct
package.json
. How can that be done from within gulp?

I tried the following but it uses the
package.json
in
myapp
not the one in the
testcontent
sub folder:

gulp.task('default', function () {
var options = {
continueOnError: true, // default = false, true means don't emit error event
pipeStdout: true, // default = false, true means stdout is written to file.contents
customTemplatingThing: "test" // content passed to gutil.template()
};
var reportOptions = {
err: true, // default = true, false means don't write err
stderr: true, // default = true, false means don't write stderr
stdout: true // default = true, false means don't write stdout
}
gulp.src('test/testcontent/')
.pipe(exec('npm install' , options))
.pipe(exec.reporter(reportOptions));
});

Answer

gulp-exec is the wrong tool for this job. In fact the authors of the gulp-exec plugin explicitly advise against using it the way you are doing:

Note: If you just want to run a command, just run the command, don't use this plugin

Instead you use the node.js built-in child_process.spawn(). You can pass the directory where the command should be executed using the cwd option:

var spawn = require('child_process').spawn;

gulp.task('default', function(done) {
  spawn('npm', ['install'], { cwd: 'test/testcontent/', stdio: 'inherit' })
    .on('close', done);
});
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