I am trying to merge multiple linux commands in one line to perform deployment operation.
svn co path to repo
mvn compile package install
If you want to execute each command only if the previous one succeeded, then combine them using the
cd /my_folder && rm *.jar && svn co path to repo && mvn compile package install
If one of the commands fails, then all other commands following it won't be executed.
If you want to execute all commands regardless of whether the previous ones failed or not, separate them with semicolons:
cd /my_folder; rm *.jar; svn co path to repo; mvn compile package install
In your case, I think you want the first case where execution of the next command depends on the success of the previous one.
You can also put all commands in a script and execute that instead:
#! /bin/sh cd /my_folder \ && rm *.jar \ && svn co path to repo \ && mvn compile package install
(The backslashes at the end of the line are there to prevent the shell from thinking that the next line is a new command; if you omit the backslashes, you would need to write the whole command in a single line.)
Save that to a file, for example
myscript, and make it executable:
chmod +x myscript
You can now execute that script like other programs on the machine. But if you don't place it inside a directory listed in your
PATH environment variable (for example
/usr/local/bin, or on some Linux distributions
~/bin), then you will need to specify the path to that script. If it's in the current directory, you execute it with:
The commands in the script work the same way as the commands in the first example; the next command only executes if the previous one succeeded. For unconditional execution of all commands, simply list each command on its own line:
#! /bin/sh cd /my_folder rm *.jar svn co path to repo mvn compile package install