null - 9 months ago 39

C++ Question

A [] is a container adaptor that provides constant time lookup of the largest (by default) element, at the expense of`std::priority_queue`

logarithmic insertion and extraction.

Why is that? I think the sorting either happens on insertion or extraction.

For example, if the sorting happens on insertion and the internal container remains sorted, wouldn't the extraction be able to happen in constant time? The top element to be removed is know and so is the next smaller one.

However, both

`std::priority_queue::push`

`std::priority_queue::pop`

## Complexity

Logarithmic number of comparisons

Why would

I guess my assumption about when and how the sorting happens (or if there's any sorting happening at all) is just wrong. Could somebody please shed some light on this?

Answer

For example, if the sorting happens on insertion and the internal container remains sorted, wouldn't the extraction be able to happen in constant time?

Extract could happen in constant time, but insertion would become `O(n)`

. You'd have to search for the place in the list to insert the new element and then shift all the other elements. `O(1)`

extraction and `O(n)`

insertion might be good for some use-cases, but not the problem that `priority_queue`

is trying to solve.

If sorting, on the other hand, happened on extraction, then you'd have `O(n lg n)`

extraction and `O(1)`

insertion. Which, again, is good for some use-cases, but that's not what `priority_queue`

does.

Rather than sorting elements, `std::priority_queue`

stores its elements^{†} in a heap, which by construction has `O(lg n)`

insertion and extraction. The structure is a tree, and insertion/extraction simply maintain the tree invariant. For some problems (like, say, search), in cases where we need to insert and extract many nodes, having `O(lg n)`

for both operations is far superior than `O(n)/O(1)`

.

As an example, and stealing images from Wikipedia, inserting the element 15 into the heap would initially place it at position `x`

:

then swap it with the `8`

(because the sorted invariant is broken):

then finally swap it with the `11`

:

In array form, the initial heap would be stored as:

```
[11, 5, 8, 3, 4]
```

and we would end up at:

```
[15, 5, 11, 3, 4, 8]
```

Extraction is just the reverse operation - bubbling down instead of bubbling up. As you see, there's no explicit "sorting" going on. We're not even touching most of the elements most of the time.

^{†}`std::priority_queue`

is a container adapter, but the container you provide should be a random access container with `O(1)`

complexities for indexing, `push_back`

, `pop_back`

, `front`

, `back`

, etc. So the choice of container (unless you make a bad one) does not affect the overall complexity of `priority_queue`

's operations.

Source (Stackoverflow)