user3437711 - 1 year ago 85

Python Question

EDIT: I SOLVED THE QUESTION BUT I WOULD APPRECIATE IF SOMEONE COULD JUST HELP ME MAKE MY CODE AS SHORT AS POSSIBLE (THE CHALLENGE WAS TO CODE IT WITH THE LEAST POSSIBLE CHARACTERS).

I was going through some python challenges online and I came across this question.

Click here to view the challenge question

I have been trying to solve it for quite a while but I am stuck in one place (heres my code):

`c = ['H','H','H','H','H','H','H','I','H','H','H','H','F','H','H','H','H','H','H','H','H','H','H','H','H',]`

c_copy = list(c)

def prt():

print("\n"+c[0]+"\t"+c[1]+"\t"+c[2]+"\t"+c[3]+"\t"+c[4]+"\n"+

c[5]+"\t"+c[6]+"\t"+c[7]+"\t"+c[8]+"\t"+c[9]+"\n"+

c[10]+"\t"+c[11]+"\t"+c[12]+"\t"+c[13]+"\t"+c[14]+"\n"+

c[15]+"\t"+c[16]+"\t"+c[17]+"\t"+c[18]+"\t"+c[19]+"\n"+

c[20]+"\t"+c[21]+"\t"+c[22]+"\t"+c[23]+"\t"+c[24])

generations = 3

while generations > 0:

for x, y in enumerate(c):

if(y == 'F'):

c_copy[x] = 'H'

if(y == 'I'):

c_copy[x] = 'F'

try:

if(c[x+1] == 'H'):

c_copy[x+1] = 'I'

if(c[x-1] == 'H'):

c_copy[x-1] = 'I'

if(c[x+5] == 'H'):

c_copy[x+5] = 'I'

if(c[x-5] == 'H'):

c_copy[x-5] = 'I'

except IndexError:

pass

c = list(c_copy)

generations = generations - 1

prt()

I know where my problem is but I cant seem to get around it. In the for loop, when i[7] == I, I change the value to its east to 'I', but when the for loop goes to i[8], it will change the value to its east again. That keeps happening until the value is not 'I'. how do I get around that? And also if someone can do the challenge in a simpler and better way, please put up your code.

Thanks

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Try using lists to keep track of the cells that need to change under certain conditions. I have also used a multidimensional list to keep track of the field of flowers.

Code with annotations:

```
#sets up the grid and the number of generations
grid=[['H','H','H','H','H'],['H','H','I','H','H'],['H','H','F','H','H'],['H','H','H','H','H'],['H','H','H','H','H']]
gen=3
#loops for each generation
for i in range(gen):
#creates lists for cells that need to be infected if possible
#and cells that need to be replanted
infect=[]
plant=[]
#loops through the grid cells
for x in range(5):
for y in range(5):
if grid[x][y]=='F':
#adds each fading cell to the list for replanting
plant.append([x,y])
if grid[x][y]=='I':
#makes the cell fade
grid[x][y]='F'
#checks if each of its neighbours is a valid grid square
#and if so adds it to the list to be infected if possible
if x>0:
infect.append([x-1,y])
if x<4:
infect.append([x+1,y])
if y>0:
infect.append([x,y-1])
if y<4:
infect.append([x,y+1])
#infects healthy cells in the 'to be infected' list
for x,y in infect:
if grid[x][y]=='H':
grid[x][y]='I'
#replants cells in the replanting list
for x,y in plant:
grid[x][y]='H'
#nicely prints the grid
for a in grid:
for b in a:
print(b,end='')
print()
```

Code without annotations:

```
grid=[['H','H','H','H','H'],['H','H','I','H','H'],['H','H','F','H','H'],['H','H','H','H','H'],['H','H','H','H','H']]
gen=3
for i in range(gen):
infect=[]
plant=[]
for x in range(5):
for y in range(5):
if grid[x][y]=='F':
plant.append([x,y])
if grid[x][y]=='I':
grid[x][y]='F'
if x>0:
infect.append([x-1,y])
if x<4:
infect.append([x+1,y])
if y>0:
infect.append([x,y-1])
if y<4:
infect.append([x,y+1])
for x,y in infect:
if grid[x][y]=='H':
grid[x][y]='I'
for x,y in plant:
grid[x][y]='H'
for a in grid:
for b in a:
print(b,end='')
print()
```

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**