user0000 - 3 months ago 6x

Python Question

I am a (very) beginner programmer, and especially new at Python.

I want to take a specified domain and a specific range and generate injective maps. For example, I could have the domain be A = [1, 2] and the range be B = [1, 3] and I would like the output to look something like "(1 -> 1, 2 ->3 ), (1 -> 3, 2 -> 1)". Or something like ((1,1),(2,3)) and ((1,3),(2,1)) would be fine.

As another example, I could take A = [2, 3] and B = [1, 2] and I would want "(2 -> 1, 3 -> 2), (2 -> 2, 3 -> 1)".

My best attempt is

`A = [1, 2]`

B = [1, 3]

C = []

for x in A:

for y in B:

C.append((x, y))

which produces the list [(1, 1), (1, 3), (2, 1), (2, 3)]. I understand why it produces that, but I can't think of any way to actually produce what I want.

I would prefer a solution using basic Python tools, like loops, lists, sets, etc.

Answer

Permute one of the two lists (`from itertools import permutations`

), and for each of the permutations do a one-to-one mapping (`zip(..)`

).

```
>>> from itertools import permutations
>>> a = [1,2,3]
>>> b = [4,5,6]
>>> [zip(a, x) for x in permutations(b)]
[[(1, 4), (2, 5), (3, 6)], [(1, 4), (2, 6), (3, 5)], [(1, 5), (2, 4), (3, 6)], [(1, 5), (2, 6), (3, 4)], [(1, 6), (2, 4), (3, 5)], [(1, 6), (2, 5), (3, 4)]]
```

Running it for your example:

```
>>> a = [1,2]
>>> b = [1,3]
>>> [zip(a, x) for x in permutations(b)]
[[(1, 1), (2, 3)], [(1, 3), (2, 1)]]
```

Source (Stackoverflow)

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