vineeth - 5 months ago 22
Python Question

# List reset in a "for" loop

guys i'm trying to do this program where i have to take a list and separate all the non unique elements and put it in a list without the changing the order of it.
for example
[1,2,3,1,3]=[1,3,1,3]
[5,5,5,5]=[5,5,5,5]
[1,2,3,4,5]=[]

So for this, I did the program in python and put some flags to help me know where i'm doing wrong.So in the program i tried to reset the list3 value( after deleting an element of it inside a loop and exiting it) but it wouldn't let me do it.so any help would be greatly appreciated. Thank you guys very much.

``````list1=[1,2,3,1,3]
list2=[]
d=0
m=0
l=len(list1)
print(l)
for x in range(0,l):
print('for loop')
list3=list1  # I used this to reset the list3 to list1 and use it in the loop but it wouldn't reset
print('this is the reset of list 3',list3)
m=list1[x]
print(m,x)
print(list3[x])
del (list3[x])

while True:
print('while loop',list3[d])

if m==list3[d]:
print('its here')
list2.append(m)
print('this is list2: ',list2)
d+=1

if d==lenght(list3)-1:
print('its here22222')
break
print(list2)

# my results were

5
for loop
this is the reset of list 3 [1, 2, 3, 1, 3]
1 0
1
while loop 2
while loop 3
while loop 1
its here
this is list2:  [1]
its here22222
for loop
this is the reset of list 3 [2, 3, 1, 3]
3 1
IndexError: list index out of range
``````

Does this do what you want?

``````#list1=[5,5,5,5,5]
list1=[1,2,3,1,3]
#list1=[1,2,3,4,5]
list2=[]

for num in list1:
if list1.count(num) > 1:
list2.append(num)

print(list2)
``````
Source (Stackoverflow)