Ash1234 - 1 year ago 54

Python Question

I have the following list with 2 elements:

`['AGCTT 6 6 35 25 10', 'AGGGT 7 7 28 29 2']`

I need to make a list or zip file such that each alphabet corresponds to its number further in the list. For example in list[0] the list/zip should read

`{"A":"6", "G":"6", "C":"35","T":"25","T":"10"}`

Can I make a list of such lists/zips that stores the corresponding vales for list[0], list[1],...list[n]?

Note: The alphabets can only be A,G,C or T, and the numbers can take anyvalue

Edit 1: Previously, I thought I could use a dictionary. But several members pointed out that this cannot be done. So I just want to make a list or zip or anything else recommended to pair the Alphabet element to its corresponding number.

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Use tuples splitting once to get the pairs, then split the second element of each pair, *zip* together:

```
l =['AGCTT 6 6 35 25 10', 'AGGGT 7 7 28 29 2']
pairs = [zip(a,b.split()) for a,b in (sub.split(None,1) for sub in l]
```

Which would give you:

```
[[('A', '6'), ('G', '6'), ('C', '35'), ('T', '25'), ('T', '10')], [('A', '7'), ('G', '7'), ('G', '28'), ('G', '29'), ('T', '2')]]
```

Of using a for loop with *list.append:*

```
l = ['AGCTT 6 6 35 25 10', 'AGGGT 7 7 28 29 2']
out = []
for a,b in (sub.split(None,1) for sub in l ):
out.append(zip(a,b))
```

If you want to convert any letter to `Z`

where the digit is < 10, you just need another loop where we check the digit in each pairing:

```
pairs = [[("Z", i ) if int(i) < 10 else (c, i) for c,i in zip(a, b.split())]
for a,b in (sub.split(None, 1) for sub in l)]
print(pairs)
```

Which would give you:

```
[[('Z', '6'), ('Z', '6'), ('C', '35'), ('T', '25'), ('T', '10')], [('Z', '7'), ('Z', '7'), ('G', '28'), ('G', '29'), ('Z', '2')]]
```

To break it into a regular loop:

```
pairs = []
for a, b in (sub.split(None, 1) for sub in l):
pairs.append([("Z", i) if int(i) < 10 else (c, i) for c, i in zip(a, b.split())])
print(pairs)
```

`[("Z", i) if int(i) < 10 else (c, i) for c, i in zip(a, b.split())]`

sets the letter to `Z`

if the corresponding digit `i`

is `< 10`

or else we just leave the letter as is.

if you want to get back to the original pairs after you just need to transpose with *zip*:

```
In [13]: l = ['AGCTT 6 6 35 25 10', 'AGGGT 7 7 28 29 2']
In [14]: pairs = [[("Z", i) if int(i) < 10 else (c, i) for c, i in zip(a, b.split())] for a, b in
....: (sub.split(None, 1) for sub in l)]
In [15]: pairs
Out[15]:
[[('Z', '6'), ('Z', '6'), ('C', '35'), ('T', '25'), ('T', '10')],
[('Z', '7'), ('Z', '7'), ('G', '28'), ('G', '29'), ('Z', '2')]]
In [16]: unzipped = [["".join(a), " ".join(b)] for a, b in (zip(*tup) for tup in pairs)]
In [17]: unzipped
Out[17]: [['ZZCTT', '6 6 35 25 10'], ['ZZGGZ', '7 7 28 29 2']]
```

`zip(*...)`

will give you the original elements back into a tuple of their own, we then just need to join the strings back together. If you wanted to get back to the total original state you could just join again:

```
In[18][ " ".join(["".join(a), " ".join(b)]) for a, b in (zip(*tup) for tup in pairs) ]
Out[19]: ['ZZCTT 6 6 35 25 10', 'ZZGGZ 7 7 28 29 2']
```

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**