Ignat Ospadov - 1 year ago 100

C Question

Hours of trying to figure this out have led to nowhere. I don't understand why the integer value of nickels is so high?

Please enter amount of change owed in $xx.xx format: $10.73

1073

Quarters: 42, remainder: 23

dimes: 2, remainder: 3

**nickels: 4195856, remainder: 3**

pennies: 3

`#include <stdio.h>`

#include <math.h>

int main ()

{

float userinput;

int cents, count, quarters, dimes, nickels, pennies, remainder;

printf("Please enter amount of change owed in $xx.xx format: $");

scanf("%f",&userinput);

while ((userinput <= 0) || (userinput < 0.01))

{

printf("Please enter a value equal to or greater than $0.01: $");

scanf("%f",&userinput);

}

cents = roundf(userinput * 100);

printf("%d\n", cents);

while ((cents / 25) >= 1) {

quarters = cents / 25;

remainder = cents % 25;

break;

}

printf("Quarters: %d, remainder: %d\n", quarters, remainder);

while ((remainder / 10) >= 1) {

dimes = remainder / 10;

remainder = remainder % 10;

break;

}

printf("dimes: %d, remainder: %d\n", dimes, remainder);

while ((remainder / 5) >= 1) {

nickels = remainder / 5;

remainder = remainder % 5;

break;

}

printf("nickels: %d, remainder: %d\n", nickels, remainder);

while ((remainder / 1) >= 1) {

pennies = remainder / 1;

break;

}

printf("pennies: %d\n", pennies);

}

Answer Source

You need to initialize your variables.

```
while ((remainder / 5) >= 1) { // If "(remainder / 5) >= 1" is false
nickels = remainder / 5; // nickles is never set
remainder = remainder % 5;
break;
}
printf("nickels: %d, remainder: %d\n", nickels, remainder); // Use of uninitialized value -> UB
```

So try to do:

```
int cents=0, count=0, quarters=0, dimes=0, nickels=0, pennies=0, remainder=0;
```

In general I think you should use `if`

instead of `while`

```
int nickels = 0;
....
....
if ((remainder / 5) >= 1) {
nickels = remainder / 5;
remainder = remainder % 5;
}
```

BTW: When using `scanf`

always check the return value.