Dustin Ryan-Roepsch - 4 months ago 38

Ruby Question

I'm implementing an HSV to RGB function in ruby, and I was hoping for syntax like this:

`def hsv_to_rgb(h, s, v)`

if (h == 0) then return 0, 0, 0 end

c = v * s

hp = h / 60.0

x = c * (1 - (hp % 2 - 1).abs)

r, g, b = case hp

when 0..1

c, x, 0

when 1..2

x, c, 0

when 2..3

0, c, x

when 3..4

0, x, c

when 4..5

x, 0, c

else

c, 0, x

end

m = v - c

return r + m, g + m, b + m

end

however, when I attempt to run this in Jruby I get the following error message:

SyntaxError: julia2.rb:60: syntax error, unexpected '\n'

when 1..2

Does something like this syntax exist in ruby?

Thanks!

Answer

Your return values in the case statement are not accepted by the ruby engine. I think you want to return an array... using the [] perhaps?

Like this:

```
def hsv_to_rgb(h, s, v)
if (h == 0) then return 0, 0, 0 end
c = v * s
hp = h / 60.0
x = c * (1 - (hp % 2 - 1).abs)
r, g, b = case hp
when 0..1
[c, x, 0]
when 1..2
[x, c, 0]
when 2..3
[0, c, x]
when 3..4
[0, x, c]
when 4..5
[x, 0, c]
else
[c, 0, x]
end
m = v - c
return r + m, g + m, b + m
end
```