Prince Dinar - 1 year ago 67
Python Question

How do i find the percentage of the most common element in a list?

I have been recently using

`Counter().most_common`
but the problem is that I need to turn the bit where it shows how much it came up into a percentage, for example:

``````[(2, 5), (10, 5)]
``````

to:

``````[(2, 50%), (10, 50%)]
``````

Is there any way of doing this using
`Counter().most_common`
, or any other method?

Here is part of my code:

``````    while count < int(DR):
count = count + int(1)
DV.append(random.randint(1, int(DI)))
if count == int(DR):
print ('\n(The Number that was rolled , the amount of times it came up):')
global x
print (Counter(DV).most_common(int((DI))))
``````

``````from collections import Counter
l = [1, 1, 2, 2, 2, 2, 2, 3, 4, 10, 10, 10, 10, 10]
c = Counter(l)
[(i, c[i] / float(len(l)) * 100.0) for i in c]
``````

Output, in the form `(element, % of total)`

``````[(1, 14.285714285714285),
(2, 35.714285714285715),
(3, 7.142857142857142),
(4, 7.142857142857142),
(10, 35.714285714285715)]
``````
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