jbsu32 - 4 months ago 12

Bash Question

I took two variables as input and after dividing them, I want to get the output rounded up to 5 decimal digits. I have tried this way ->

`sum=12`

n=7

output=$("scale=5;sum/n"|bc)

echo $output

My code isn't showing any output. What can I do??

If

`sum=3345699`

`n=1000000`

`(sum/n)=3.345699`

`3.34570`

Answer

The problem here is that you missed the `echo`

(or `printf`

or any other thing) to provide the data to `bc`

:

```
$ echo "scale=5; 12/7" | bc
1.71428
```

Also, as noted by cnicutar in comments, you need to use `$`

to refer to the variables. `sum`

is a string, `$sum`

is the value of the variable `sum`

.

All together, your snippet should be like:

```
sum=12
n=7
output=$(echo "scale=5;$sum/$n" | bc)
echo "$output"
```

This returns `1.71428`

.

Otherwise, with `"scale=5;sum/n"|bc`

you are just piping an assignment and makes `bc`

fail:

```
$ "scale=5;sum/n"|bc
bash: scale=5;sum/n: No such file or directory
```

You then say that you want to have the result rounded, which does not happen right now:

```
$ sum=3345699
$ n=1000000
$ echo "scale=5;($sum/$n)" | bc
3.34569
```

This needs a different approach, since `bc`

does not round. You can use `printf`

together with `%.Xf`

to round to `X`

decimal numbers, which does:

```
$ printf "%.5f" "$(echo "scale=10;$sum/$n" | bc)"
3.34570
```

See I give it a big scale, so that then `printf`

has decimals numbers enough to round properly.