Show/Hide content by checking 2 differen URLS first

Question

I'm running a code that displays content based on the url. If the user is in page X, the page displays the content number 1 and hides number 2, if he's in page Y, it displays the content number 2 and hides number 1. It works, but I would like to add a second URL to be checked.

My code is as follows:

jQuery(document).ready(function($){



  var url = document.location.href;

    if(url == "http://w.com/") {

$(".banner1").show();

$(".adsenselistingtop").show();

$("#leheaderbanner").hide();

$("#showhide-in-home").hide();



  } else {

      $(".banner1").hide();

      $(".adsenselistingtop").hide();

      $("#leheaderbanner").show();

      $("#showhide-in-home").show();

  }







});

I tried using something like this, but it didn't work:

 if(url == "http://w.com/" && url == "http://w.com/index.php") {

Answer 1

Use OR instead of AND as the URL can be either of them.

if(url == "http://w.com/" || url == "http://w.com/index.php")

Show/Hide content by checking 2 differen URLS first

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