reindeer - 1 year ago 140
Python Question

# Get minimum x and y from 2D numpy array of points

Given a numpy 2D array of points, aka 3D array with size of the 3rd dimension equals to 2, how do I get the minimum x and y coordinate over all points?

Examples:

First:

I edited my original example, since it was wrong.

``````data = np.array(
[[[ 0,  1],
[ 2,  3],
[ 4,  5]],

[[11, 12],
[13, 14],
[15, 16]]])

minx = 0 # data[0][0][0]
miny = 1 # data[0][0][1]
``````

4 x 4 x 2:

Second:

``````array([[[ 0, 77],
[29, 12],
[28, 71],
[46, 17]],
[[45, 76],
[33, 82],
[14, 17],
[ 3, 18]],
[[99, 40],
[96,  3],
[74, 60],
[ 4, 57]],
[[67, 57],
[23, 81],
[12, 12],
[45, 98]]])

minx = 0 # data[0][0][0]
miny = 3 # data[2][1][1]
``````

Is there an easy way to get now the minimum x and y coordinates of all points of the data? I played around with amin and different axis values, but nothing worked.

Clarification:

My array stores positions from different robots over time. First dimension is time, second is the index of an robot. The third dimension is then either x or y of a robots for a given time.

Since I want to draw their paths to pixels, I need to normalize my data, so that the points are as close as possible to the origin without getting negative. I thought that subtracting [minx,miny] from every point will do that for me.

Seems you need consecutive min alongaxis. For your first example:

``````>>> np.min(np.min(data, axis=1), axis=0)
array([ 0, 1])
``````

For the second:

``````>>> np.min(np.min(data, axis=1), axis=0)
array([0, 3])
``````

The same expression can be stated (in numpy older than 1.7), as pointed out by @Jamie, s

``````>>> np.min(data, axis=(1, 0))
array([0, 3])
``````
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