AhmedLo - 1 year ago 80
Java Question

# Formula and running time

I have spent so much time trying to find the formula for this code, but still nothing .. I know the running time but the question really is, what if n = 100 for example, how many line of output will this code print without tracing through ? So, if I found the exact formula, I would answer the question without tracing. This is the code

``````  int i, j, k;

for( i = 1; i <= n; i++ )
for ( j = i+1; j <= n; j++ )
for( k = j+1; k <= n; k++ )
{
System.out.println( i + " " + j + " " + k);
}
``````

I have a feeling that you are requiring a formula to get number of iteration the nested loops will.

``````  for( i = 1; i <= n; i++ )
for ( j = i+1; j <= n; j++ )
for( k = j+1; k <= n; k++ )
``````

For those loops, the number of iterations will be:

``````(n*(n-1)*(n-2))/6, where n > 2.
``````

Generic formula for above kind loops:

``````(n*(n-1)* ... *(n-r+1)) / r!, where n > r-1.
``````

Here, r = number of loops

For example: when n = 20 and r = 3, number of iterations will be = (20*19*18) / 3! = 1140

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