Reading specific value from a text file extensi .job

Question

i have question, for get specific contain of file. i already get all data from many file .job extension, now i want to get data just in JobID rows so i can get all data JobID rows from many file .job, i want the output be "115518024" and more like the example. sorry my english. thanks

CODE GET DATA

foreach (glob("C://xampp/htdocs/LogMesinMutoh/*.job") as $file) { 

$file_handle = fopen($file, "r");

while (!feof($file_handle)) {

    $line = fgets($file_handle);

    echo $line;

}

fclose($file_handle);

}

DATA FILE

[JobSetting]

File=D:\Shared\print\2017\september\26\Printing Ira\Cat Pattern EKA SITOMPUL 55X55.tif

PrintSetup=VJ-1624W_MURIM_HP100_4PASS.tps

RaPInfoFile=VJ-1624

JobID=115518024

WorkType=3

SourceSizeX=549.980530

SourceSizeY=549.980530

DestSizeX=549.980530

DestSizeY=549.980530

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Answer 1

I assume $str is a file content

$str = "File=D:\Shared\print\2017\september\26\Printing Ira\Cat
Pattern EKA SITOMPUL 55X55.tif
PrintSetup=VJ-1624W_MURIM_HP100_4PASS.tps RaPInfoFile=VJ-1624
JobID=115518024 WorkType=3 SourceSizeX=549.980530
SourceSizeY=549.980530 DestSizeX=549.980530 DestSizeY=549.980530";


$regex = '/JobID=(\w+)/';

preg_match($regex, $str, $matches);

print_r($matches);

You will get your output at $matches[1]

Reading specific value from a text file extensi .job

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