bobimo - 27 days ago 17

Python Question

I have been thinking about this issue and I can't figure it out. Perhaps you can assist me. The problem is my code isn't working to output 1000 digits of pi in the python coding language.

Here's my code:

`def make_pi():`

q, r, t, k, m, x = 1, 0, 1, 1, 3, 3

while True:

if 4 * q + r - t < m * t:

yield m

q, r, t, k, m, x = (10*q, 10*(r-m*t), t, k, (10*(3*q+r))//t - 10*m, x)

else:

q, r, t, k, m, x = (q*k, (2*q+r)*x, t*x, k+1, (q*(7*k+2)+r*x)//(t*x), x+2)

digits = make_pi()

pi_list = []

my_array = []

for i in range(1000):

my_array.append(str("hello, I'm an element in an array \n" ))

big_string = "".join(my_array)

print "here is a big string:\n %s" % big_string

I know this code can be fixed to work, but I'm not sure what to fix...The print statement saying here is a big string and the

`my_array.append(str("hello, im an element in an array \n))`

Answer

Run this

```
def make_pi():
q, r, t, k, m, x = 1, 0, 1, 1, 3, 3
for j in range(1000):
if 4 * q + r - t < m * t:
yield m
q, r, t, k, m, x = 10*q, 10*(r-m*t), t, k, (10*(3*q+r))//t - 10*m, x
else:
q, r, t, k, m, x = q*k, (2*q+r)*x, t*x, k+1, (q*(7*k+2)+r*x)//(t*x), x+2
digits = make_pi()
pi_list = []
my_array = []
for i in make_pi():
my_array.append(str(i))
my_array = my_array[:1] + ['.'] + my_array[1:]
big_string = "".join(my_array)
print "here is a big string:\n %s" % big_string
```

And read about `yield`

operator from here:
The Python yield keyword explained

Here is the answer:

```
3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337
```

Source (Stackoverflow)

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