Kevin Hoffman Kevin Hoffman - 1 year ago 128
AngularJS Question

How do I ignore the initial load when watching model changes in AngularJS?

I have a web page that serves as the editor for a single entity, which sits as a deep graph in the $scope.fieldcontainer property. After I get a response from my REST API (via $resource), I add a watch to 'fieldcontainer'. I am using this watch to detect if the page/entity is "dirty". Right now I'm making the save button bounce but really I want to make the save button invisible until the user dirties the model.

What I am getting is a single trigger of the watch, which I think is happening because the .fieldcontainer = ... assignment takes place immediately after I create my watch. I was thinking of just using a "dirtyCount" property to absorb the initial false alarm but that feels very hacky ... and I figured there has to be an "Angular idiomatic" way to deal with this - I'm not the only one using a watch to detect a dirty model.

Here's the code where I set my watch:

$scope.fieldcontainer = Message.get({id: $scope.entityId },
function(message,headers) {
function() {
console.log("model is dirty.");
if ($scope.visibility.saveButton) {
$('#saveMessageButtonRow').effect("bounce", { times:5, direction: 'right' }, 300);
}, true);

I just keep thinking there's got to be a cleaner way to do this than guarding my "UI dirtying" code with an "if (dirtyCount >0)"...

Answer Source

set a flag just before the initial load,

var initializing = true

and then when the first $watch fires, do

$scope.$watch('fieldcontainer', function() {
  if (initializing) {
    $timeout(function() { initializing = false; });
  } else {
    // do whatever you were going to do

The flag will be tear down just at the end of the current digest cycle, so next change won't be blocked.

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