fip - 10 months ago 39

Python Question

I suppose to write a code that prints out the value of a number that occurs twice in the list given, but they don't allow us to use a built in function on python. How would I be able to write it without using enumerate?

`def find_second_occurrence(xs,v):`

count = 0

value = None

for i, x in enumerate(xs):

if v == x:

count += 1

if count == 2:

return i

if (count < 2):

return value

Answer Source

`enumerate(sequence)`

is pretty much similar to a construct of the form:

```
for i in range(len(sequence)):
# get sequence[i] and return i and sequence[i] for all i's
```

So, in your code, replacing `enumerate`

altogether could be done by:

```
for i in range(len(xs)):
x = xs[i]
if v == x:
count += 1
if count == 2:
return i
```

Or, without assigning to an `x`

name to temporarily hold the sequence item:

```
for i in range(len(xs)):
if v == xs[i]:
count += 1
if count == 2:
return i
```

Creating a little `my_enumerate`

function, is also rather simple:

```
def my_enumerate(sequence, start=0):
for i in range(len(sequence)):
yield start+i, sequence[i]
```

`start`

has also been defined as to match that as used in `enumerate`

and gets a default value of `0`

.

Rather than `yield`

ing values (if this is mystifying to you), you can create a list (generator comprehensions are similar to `yield`

ing) comprehension and return that instead:

```
def my_enumerate(sequence, start=0):
return [(start+i, sequence[i]) for i in range(len(sequence))]
```