'(match_start1)...(match_start2)...(match_end)' find the shortest string match

Question

'\D\d{2,5}?.+?CA.??[ \-\.\_]*(?:\d{5})?', 

the string is '6785 56767at435 hjfioej st. CA.    94827ifojwnf 93842'

Both

't435 hjfioej st. CA. 94827'

and

' 56767at435 hjfioej st. CA. 94827'

should match, but the procedure given in the above post is not giving the minimum match.

Please help.

Answer 1

re.findall('(?=(\D\d{2,5}?.+?CA.?[ -._]*(?:\d{5})?))','6785 56767at435 hjfioej st. CA. 94827ifojwnf 93842')

So this will do the trick, then output the one of the minimum length.

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