Vincent Vincent - 2 months ago 25
PHP Question

Using namespace in if / else statements

I am manipulating the same file to manage two external api classes.

One api class is based on namespaces, the other one is not.

What I would like to do is something like this:

if($api == 'foo'){
require_once('foo.php');
}
if($api == 'bar'){
require_once('bar.php');
use xxxx\TheClass;
}


The problem is that when I do so, the following error message is returned:

Parse error: syntax error, unexpected T_USE in etc...


Question 1: Do I have to use two different files to manage the two classes or is it possible to manage both while using namespaces in the document? From what I see, it does not seem to be.

Question 2: Why namespaces could not be used inside if() statements?

Thank you for your help

Answer

Please see Scoping rules for importing

The use keyword must be declared in the outermost scope of a file (the global scope) or inside namespace declarations. This is because the importing is done at compile time and not runtime, so it cannot be block scoped.

All use does is import a symbol name into the current namespace. I would just omit the import and use the fully qualified class name, eg

switch ($api) {
    case 'foo' :
        require_once('foo.php');
        $someVar = new SomeClass();
        break;
    case 'bar' :
       require_once('bar.php');
       $someVar = new \xxxx\TheClass();
       break;
   default :
       throw new UnexpectedValueException($api);
}

You can also simply add the use statement to the top of your script. Adding it does not commit you to including any files and it does not require the symbol to be known, eg

use xxxx\TheClass;

switch ($api) {
    case 'foo' :
        require_once('foo.php');
        $someVar = new SomeClass();
        break;
    case 'bar' :
       require_once('bar.php');
       $someVar = new TheClass(); // imported above
       break;
   default :
       throw new UnexpectedValueException($api);
}
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