RedHatcc RedHatcc - 10 months ago 67
Java Question

Java String - See if a string contains only numbers and not letters

I have a string that I load throughout my application, and it changes from numbers to letters and such. I have a simple

statement to see if it contains letters or numbers but, something isn't quite working correctly. Here is a snippet.

String text = "abc";
String number;

if (text.contains("[a-zA-Z]+") == false && text.length() > 2) {
number = text;

Although the
variable does contain letters, the condition returns as
. The and
should eval as both conditions having to be
in order to process the
number = text;



I was able to solve this by using this following code provided by a comment on this question. All other post are valid as well!

What I used that worked came from the first comment. Although all the example codes provided seems to be valid as well!

String text = "abc";
String number;

if (Pattern.matches("[a-zA-Z]+", text) == false && text.length() > 2) {
number = text;

Answer Source

If you'll be processing the number as text, then change:

if (text.contains("[a-zA-Z]+") == false && text.length() > 2){


if (text.matches("[0-9]+") && text.length() > 2) {

Instead of checking that the string doesn't contain alphabetic characters, check to be sure it contains only numerics.

If you actually want to use the numeric value, use Integer.parseInt() or Double.parseDouble() as others have explained below.

As a side note, it's generally considered bad practice to compare boolean values to true or false. Just use if (condition) or if (!condition).