user2725742 - 7 months ago 55
Python Question

Converting a hex value of a string to an Ascii character with a hex value

Specifically in Python 2.4, which is unfortunately old, I need to convert a length into hex value. Length of 1 would be '\x00\x01' while a length of 65535 would be '\xFF\xFF'.

``````import struct

hexdict = {'0':'\x00\x00', '1':'\x00\x01', '2':'\x00\x02', '3':'\x00\x03', '4':'\x00\x04', '5':'\x00\x05', '6':'\x00\x06', '7':'\x00\x07', '8':'\x00\x08', '9':'\x00\x09', 'a':'\x00\x0a', 'b':'\x00\x0b', 'c':'\x00\x0c', 'd':'\x00\x0d', 'e':'\x00\x0e', 'f':'\x00\x0f'}

def convert(int_value): # Not in original request
encoded = format(int_value, 'x')
length = len(encoded)
encoded = encoded.zfill(length+length%2)
retval = encoded.decode('hex')
if x < 256:
retval = '\x00' + retval
return retval

for x in range(16):
print hexdict[str(hex(x)[-1])] # Original, terrible method
print convert(x) # Slightly better method
print struct.pack(">H", x) # Best method
``````

Aside from having a dictionary like above, how can I convert an arbitrary number <= 65535 into this hex string representation, filling 2 bytes of space?

Thanks to Linuxios and an answer I found while waiting for that answer, I have found three methods to do this. Obviously, Linuxios' answer is the best, unless for some reason importing struct is not desired.

Using Python's built-in `struct` package:

``````import struct
struct.pack(">H", x)
``````

For example, `struct.pack(">H", 1)` gives `'\x00\x01'` and `struct.pack(">H", 65535)` gives `'\xff\xff'`.