Yair B. Yair B. - 1 year ago 246
HTTP Question

How to create HTTP GET request Scapy?

I need to create HTTP GET request and save the data response.
I tried to use this:

syn = IP(dst=URL) / TCP(dport=80, flags='S')
syn_ack = sr1(syn)
getStr = 'GET / HTTP/1.1\r\nHost: www.google.com\r\n\r\n'
request = IP(dst='www.google.com') / TCP(dport=80, sport=syn_ack[TCP].dport,
seq=syn_ack[TCP].ack, ack=syn_ack[TCP].seq + 1, flags='A') / getStr
reply = sr1(request)
print reply.show()

But when I print
I don't see any data response.
In addition, when I checked in 'Wireshark' I got SYN, SYN/ACK but I didn't get an ACK.

The problem


I try to do that now:

# Import scapy
from scapy.all import *

# Print info header
print "[*] ACK-GET example -- Thijs 'Thice' Bosschert, 06-06-2011"

# Prepare GET statement
get='GET / HTTP/1.0\n\n'

# Set up target IP

# Generate random source port number

# Create SYN packet
SYN=ip/TCP(sport=port, dport=80, flags="S", seq=42)

# Send SYN and receive SYN,ACK
print "\n[*] Sending SYN packet"

# Create ACK with GET request
ACK=ip/TCP(sport=SYNACK.dport, dport=80, flags="A", seq=SYNACK.ack, ack=SYNACK.seq + 1) / get

# SEND our ACK-GET request
print "\n[*] Sending ACK-GET packet"

# print reply from server
print "\n[*] Reply from server:"
print reply.show()

print '\n[*] Done!'

but its print me in reply from server;

0000 IP / TCP > A / Raw ==>
IP / TCP > A / Padding None

And I need Line-based text data: text/html.

Answer Source

You are sending a SYN and correctly receiving a SYN_ACK. At this point, you should generate and send an ACK based on the SYN_ACK that you've received, and THEN finally transmit the HTTP GET request. It seems that you are somewhat confused about the TCP 3-way handshake mechanism. In short, you are not supposed to 'get' an ACK, you are supposed to generate and send this yourself.

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