Bash Question

Fastest way to print a certain portion of a file using bash commands

currently I am using sed to print the required portion of the file. For example, I used the below command

sed -n 89001,89009p

However, it is pretty slow as the file size is increasing (my file is currently 6.8 GB). I have tried to follow this link and used the command

sed -n '89001,89009{p;q}'

But, this command is only printing the 89001th line. Kindly, help me.


The syntax is a little bit different:

sed -n '89001,89009p;89009q'


Since there is also an answer with awk I made small comparison and as I thought - sed is a little bit faster:

$ wc -l large-file 
100000000 large-file
$ du -h large-file 
954M    large-file
$ time sed -n '890000,890010p;890010q' large-file > /dev/null

real    0m0.141s
user    0m0.068s
sys 0m0.000s
$ time awk 'NR>=890000{print} NR==890010{exit}' large-file > /dev/null

real    0m0.433s
user    0m0.208s
sys 0m0.008s`