Dave Matthew - 18 days ago 8
Python Question

# How can I check if a variable exists in multiple lists?

Here's an excerpt from my code!

``````division = ["Division","Divide","/","div"]
multiplication =["*","x","times","multiply","multiplication","multiple"]
subtraction = ["-",'minus','subtract','subtraction']
root = ['root','squareroot','square root']
square = ['square','squared','power 2']

choice = input('calculation type')
print(choice == (division or multiplication or subtraction or addition))
``````

So far, it only gives "False".
How can I check if a variable exists in multiple lists?
I've tried to make lists inside of lists but I still get "False", Here's the code of that...

``````division = ["Division","Divide","/","div"]
multiplication = ["*","x","times","multiply","multiplication","multiple"]
subtraction = ["-",'minus','subtract','subtraction']
root = ['root','squareroot','square root']
square = ['square','squared','power 2']
basic_single = [root,square]
choice = input('calculation type')
print(choice == basic_double or basic_single)
``````

Any help would be appreciated! :D thank you!!!

Test whether the `choice` is in `any` of the lists:

``````any(choice in ls for ls in [division, multiplication, subtraction, addition])
``````

`any` returns True if at least one of the elements of the given iterable are truthy.

`choice in ls` tests whether choice is an element of the list.

`choice in ls for ls in [division, multiplication, subtraction, addition]` is a generator comprehension, meaning it's an iterator that returns the result of `choice in ls` for any possible `ls` in `[division, multiplication, subtraction, addition]`.

If one of those lists contains the `choice`, `any` will return True, False otherwise.