Stanley Wilkins Stanley Wilkins - 1 year ago 352
Python Question

Automate the Boring Stuff Chapter 6 Table Printer Almost Done

In this section, they want us to create this table:

apples Alice dogs
oranges Bob cats
cherries Carol moose
banana David goose

It must be justified to the right, and the input is tableData. Here's my code:

tableData=[['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
for m in tableData:
for n in m:


#print (lists['list:', 1])
#print (longest)

for m in range(len(tableData[0])):
for n in range(len(tableData)):
print (tableData[n][m],end=" ")
print ("".rjust(lists['list:', 1],"-"))

I'm almost done except for one thing, I can't make it right-justified. This output is the closest I came so far.

apples Alice dogs ---------------------------
oranges Bob cats ---------------------------
cherries Carol moose ---------------------------
banana David goose ---------------------------

If I put rjust inside the inner for-loop the output is much different:

apples-------------------------- Alice-------------------------- dogs--------------------------
oranges-------------------------- Bob-------------------------- cats--------------------------
cherries-------------------------- Carol-------------------------- moose--------------------------
banana-------------------------- David-------------------------- goose--------------------------

Answer Source

Here's an alternate method that perhaps you could apply to your own code. I first took tableData and sorted it out into a dictionary so it's easier to work with. After that I found the longest list in terms of characters. This allows us to know how far over the shorter lists should go. Finally, I printed out each lists adding spaces in front of the shorter ones based on the difference from the longest.

# orginal data
tableData=[['apples', 'oranges', 'cherries', 'banana'],
        ['Alice', 'Bob', 'Carol', 'David'],
        ['dogs', 'cats', 'moose', 'goose']]

# empty dictonary for sorting the data
newTable = {0:[], 1:[], 2:[], 3:[]}

# iterate through each list in tableData
for li in tableData:
    for i in range(len(li)):
        # put each item of tableData into newTable by index

# determine the longest list by number of total characters
# for instance ['apples', 'Alice', 'dogs'] would be 15 characters
# we will start with longest being zero at the start
longest = 0
# iterate through newTable
# for example the first key:value will be 0:['apples', 'Alice', 'dogs']
# we only really care about the value (the list) in this case
for key, value in newTable.items():
    # determine the total characters in each list
    # so effectively len('applesAlicedogs') for the first list
    length = len(''.join(value))
    # if the length is the longest length so far,
    # make that equal longest
    if length > longest:
        longest = length

# we will loop through the newTable one last time
# printing spaces infront of each list equal to the difference
# between the length of the longest list and length of the current list
# this way it's all nice and tidy to the right
for key, value in newTable.items():
    print(' ' * (longest - len(''.join(value))) + ' '.join(value))
Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download