Raaj - 1 year ago 84
R Question

# R : function to generate a mixture distribution

I need to generate samples from a mixed distribution

• 40% samples come from Gaussian(mean=2,sd=8)

• 20% samples come from Cauchy(location=25,scale=2)

• 40% samples come from Gaussian(mean = 10, sd=6)

To do this, i wrote the following function :

``````dmix <- function(x){
prob <- (0.4 * dnorm(x,mean=2,sd=8)) + (0.2 * dcauchy(x,location=25,scale=2)) + (0.4 * dnorm(x,mean=10,sd=6))
return (prob)
}
``````

And then tested with:

``````foo = seq(-5,5,by = 0.01)
vector = NULL
for (i in 1:1000){
vector[i] <- dmix(foo[i])
}
hist(vector)
``````

I'm getting a histogram like this (which I know is wrong) -

What am I doing wrong? Can anyone give some pointers please?

There are of course other ways to do this, but the distr package makes it pretty darned simple. (See also this answer for another example and some more details about distr and friends).

``````library(distr)

## Construct the distribution object.
myMix <- UnivarMixingDistribution(Norm(mean=2, sd=8),
Cauchy(location=25, scale=2),
Norm(mean=10, sd=6),
mixCoeff=c(0.4, 0.2, 0.4))
## ... and then a function for sampling random variates from it
rmyMix <- r(myMix)

## Sample a million random variates, and plot (part of) their histogram
x <- rmyMix(1e6)
hist(x[x>-100 & x<100], breaks=100, col="grey", main="")
``````

And if you'd just like a direct look at your mixture distribution's pdf, do:

``````plot(myMix, to.draw.arg="d")
``````