Taiwosam - 1 month ago 5x

Python Question

How do I write an equivalent of the code below using map and filter?

`res = []`

for x in range(5):

if x % 2 == 0:

for y in range(5):

if y % 2 == 1:

res.append((x, y))

This is the expected result:

`[(0, 1), (0, 3), (2, 1), (2, 3), (4, 1), (4, 3)]`

Here's the code I wrote, but it doesn't seem to work:

`list( map(( lambda x,y: (x,y)), filter((lambda x: x%2 == 0), range(5)), filter((lambda y: y%2 != 0), range(5))))`

Answer

You can write it as (in Python 2.x):

```
xs = filter(lambda x: x % 2 == 0, range(5))
ys = filter(lambda y: y % 2 == 1, range(5))
res = [(x, y) for x in xs for y in ys]
```

This also uses a list comprehension.

In Python 3.x:

```
xs = list(filter(lambda x: x % 2 == 0, range(5)))
ys = list(filter(lambda y: y % 2 == 1, range(5)))
res = [(x, y) for x in xs for y in ys]
```

Source (Stackoverflow)

Comments