Oeufcoque Penteano Oeufcoque Penteano - 9 days ago 4x
Python Question

Good Infix to Prefix implementation in Python that covers more operators (e.g. <, <=, etc) of a C program?

I have been looking without much luck for an implementation of Python that converts infix to prefix that ranges on a sufficient amount of arithmetic and logic operators and care about its properties on a good python implementation. More specifically I am interested on the operators that would appear on a conditional clause of a C program. (e.g. it would transform

a > 0 && b > 1
in prefix.

Since I am still newbie to Python I would appreciate if anyone could offer me the implementation or some tips on going about this.

I found an implementation around the internet that I lost the reference for (below), but it only cares about the more simple operators. I am a little clueless on how to do this on this version, and if anyone knew a version that already included all the operators I would appreciate to avoid any operator being ignored by accident.

Such implementation should also account for parenthesis.

Please comment if you need more details!

Thank you.

def parse(s):
for operator in ["+-", "*/"]:
depth = 0
for p in xrange(len(s) - 1, -1, -1):
if s[p] == ')': depth += 1
if s[p] == '(': depth -= 1
if not depth and s[p] in operator:
return [s[p]] + parse(s[:p]) + parse(s[p+1:])
s = s.strip()
if s[0] == '(':
return parse(s[1:-1])
return [s]


I don't quite have time to write an implementation right now, but here is an implementation I wrote that converts infix to postfix (reverse polish) notation (reference: Shunting-yard algorithm). It shouldn't be too hard to do the modify this algorithm to do prefix instead:

  • ops is the set() of operator tokens.
  • prec is a dict() containing operand tokens as keys and an integer for operator precedence as it's values (e.g { "+": 0, "-": 0, "*": 1, "/": 1})
  • Use regular expressions to parse a string into a list of tokens.

(really, ops and prec could just be combined)

def infix_postfix(tokens):
    output = []
    stack = []
    for item in tokens:
        #pop elements while elements have lower precedence
        if item in ops:
            while stack and prec[stack[-1]] >= prec[item]:
        #delay precedence. append to stack
        elif item == "(":
        #flush output until "(" is reached
        elif item == ")":
            while stack and stack[-1] != "(":
            #should be "("
            print stack.pop()
        #operand. append to output stream
    #flush stack to output
    while stack:
    return output