Hans - 1 year ago 179
R Question

R optim() L-BFGS-B needs finite values of 'fn' - Weibull

I try to estimate the three parameters a, b0 and b1 with the

`optim()`
function. But I always get the error:
Error in optim(par = c(1, 1, 1), fn = logweibull, method = "L-BFGS-B", :
L-BFGS-B needs finite values of 'fn'

``````t<-c(6,6,6,6,7,9,10,10,11,13,16,17,19,20,22,23,25,32,32,34,35,1,1,2,2,3,4,4,5,5,8,8,8,8,11,11,12,12,15,17,22,23)
d<-c(0,1,1,1,1,0,0,1,0,1,1,0,0,0,1,1,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1)
X<-c(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

logweibull <- function (a,b0,b1) {a <- v[1];b0 <- v[2]; b1 <- v[3];
sum (d*log(t^a*exp(b0+X*b1)-t^a*exp(b0+X*b1))) + sum (d + log((a*t^(a-1))/t^a)) }

v<-c(1,1,1)

optim( par=c(1,1,1) ,fn = logweibull, method = "L-BFGS-B",lower = c(0.1, 0.1,0.1), upper = c(100, 100,100),control = list(fnscale = -1) )
``````

Can you help me? Do you know what I did wrong?

You may also consider

(1) passing the additional data variables to the objective function along with the parameters you want to estimate.

(3) the original objective function can be further simplified (as below)

``````logweibull <- function (v,t,d,X) {
a <- v[1]
b0 <- v[2]
b1 <- v[3]
sum(d*(1+a*log(t)+b0+X*b1) - t^a*exp(b0+X*b1) + log(a/t)) # simplified function
}

a <- v[1]
b0 <- v[2]
b1 <- v[3]
c(sum(d*log(t) - t^a*log(t)*exp(b0+X*b1) + 1/a),
sum(d-t^a*exp(b0+X*b1)),
sum(d*X - t^a*X*exp(b0+X*b1)))
}

optim(par=c(1,1,1), fn = logweibull, gr = grad.logweibull,
method = "L-BFGS-B",
lower = c(0.1, 0.1,0.1),
upper = c(100, 100,100),
control = list(fnscale = -1),
t=t, d=d, X=X)
``````

with output

``````\$par
[1] 0.2604334 0.1000000 0.1000000

\$value
[1] -191.5938

\$counts