Javascript Question
Javascript function parameters checking
I have a function with 4 parameters for building json request. I need to check parameters for 'undefined'/empty value
function funName(param1, param2, param3, param4) {
if (param1 !== '' && param2 !== '' && param3 !== '' && param4 !== '') {
url = https://example.com/api/posts.json?' + param1 + param2 + param3 + param4;
}
else if {
if (param1 == '' && param2 !== '' && param3 !== '' && param4 !== '') {
url = https://example.com/api/posts.json?' + param2 + param3 + param4;
}
// code
};
How to check more elegant ?
Answer Source
For your purposes you can do this:
function funName(param1, param2, param3, param4) {
var url = 'https://example.com/api/posts.json?' +
(param1 || '') + (param2 || '') + (param3 || '') + (param4 || '');
// rest of your code.
}
Or with ES6:
function funName(/* params */) {
var url = 'https://example.com/api/posts.json?' +
[...arguments].filter(p => p).join('');
// rest of your code.
console.log(url);
}
funName('a=1', '&b=2', '');