Fresheyeball - 1 year ago 147

Javascript Question

I have an array that looks like the following:

`array = [[1, 5], [4, 7], [3, 8], [2, 3],`

[12, 4], [6, 6], [4, 1], [3, 2],

[8, 14]]

What I need is the largest number from the first value of the sets, so in this case

`12`

Looking at some examples online, the best way I saw to accomplish this is :

`Math.max.apply Math, array`

Problem is, this only works with single dimensional arrays. How would I impliment this for my senario? (jquery allowed)

It wasn't part of the question, but I needed both the min and max from the array, and that changes things a little.

`unless device.IE`

justTheDates = magnitudeArray.map (i) -> i[0]

@earliest = Math.min.apply Math, justTheDates

@latest = Math.max.apply Math, justTheDates

else

@earliest = magnitudeArray[0][0]

@latest = magnitudeArray[0][0]

for magnitudeItem in magnitudeArray

@earliest = magnitudeItem[0] if magnitudeItem[0] < @earliest

@latest = magnitudeItem[0] if magnitudeItem[0] > @latest

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Answer Source

You can use `.reduce()`

...

```
array.reduce(function(max, arr) {
return Math.max(max, arr[0]);
}, -Infinity)
```

Here's a version that doesn't use `Math.max`

...

```
array.reduce(function(max, arr) {
return max >= arr[0] ? max : arr[0];
}, -Infinity);
```

...and a jsPerf test.

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