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Takkun Takkun - 8 months ago 43
C Question

How to create a md5 hash of a string in C?

I've found some md5 code that consists of the following prototypes...

I've been trying to find out where I have to put the string I want to hash, what functions I need to call, and where to find the string once it has been hashed. I'm confused with regards to what the uint32 buf[4] and uint32 bits[2] are in the struct.

struct MD5Context {
uint32 buf[4];
uint32 bits[2];
unsigned char in[64];

* Start MD5 accumulation. Set bit count to 0 and buffer to mysterious
* initialization constants.
void MD5Init(struct MD5Context *context);

* Update context to reflect the concatenation of another buffer full
* of bytes.
void MD5Update(struct MD5Context *context, unsigned char const *buf, unsigned len);

* Final wrapup - pad to 64-byte boundary with the bit pattern
* 1 0* (64-bit count of bits processed, MSB-first)
void MD5Final(unsigned char digest[16], struct MD5Context *context);

* The core of the MD5 algorithm, this alters an existing MD5 hash to
* reflect the addition of 16 longwords of new data. MD5Update blocks
* the data and converts bytes into longwords for this routine.
void MD5Transform(uint32 buf[4], uint32 const in[16]);


I don't know this particular library, but I've used very similar calls. So this is my best guess:

unsigned char digest[16];
const char* string = "Hello World";
struct MD5Context context;
MD5Update(&context, string, strlen(string));
MD5Final(digest, &context);

This will give you back an integer representation of the hash. You can then turn this into a hex representation if you want to pass it around as a string.

char md5string[33];
for(int i = 0; i < 16; ++i)
    sprintf(&md5string[i*2], "%02x", (unsigned int)digest[i]);