poorvankBhatia - 1 month ago 18

C Question

Generic root of a number is defined as the sum of digits of a number until we get a single digit.

For example:

Generic root of 456: 4 + 5 + 6 = 15 since 15 is two digit numbers so 1 + 5 = 6

So, generic root of 456 = 6

I solved this problem by recursively adding the digits of the number until a single digit number is obtained and the program worked fine. I searched the web and found a very small solution for it which i was unable to understand:

`#include<stdio.h>`

int main()

{ int n,x;

printf("Enter no");

scanf("%d",&n);

printf("Generic root: %d",(x=n%9)?x:9);

return 0;

}

I am not able to understand how the ternary operator is working here!? How is it calculating the Generic root of a number

Answer

A number *n* modulus 9 returns either its root or 0, in which case the root is 9.

- Calculate n % 9 to get the root
- If the result is 0, then the root is 9

So `(x=n%9)?x:9`

means that if n mod 9 is zero, assign 9.

You can also achieve this without the ternary operator:

```
x = 1+((n-1)%9)
```

The modulus 9 trick is called the *congruence formula*.

Source (Stackoverflow)

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